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In the circuit (Fig.) what is potential ...

In the circuit (Fig.) what is potential difference `V_(B) - V_(A)` (in `V`) when current `I` is `5 A` and is decreasing at the rate of `10^(3) A s^(-1)`

Text Solution

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The correct Answer is:
`(8)`
`V_(A) - IR + E - L (dI)/(dt) = V_(B)`
`rArr V_(A) - 5 xx 1 + 8 - 5 xx 10^(-3)(-10^(-3)) = V_(B)`
`rArr V_(B) - B_(A) = 8V`
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