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A short-circuited coil is placed in a ti...

A short-circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be quadrupled and the wire radius halved, then the electrical power dissipated would be

A

halved

B

the same

C

doubled

D

quadrupled

Text Solution

Verified by Experts

The correct Answer is:
B
`P_(1) = (e_(1)^(2))/(R_(1))`, `e_(2) = 4e_(1)`
`R_(1) = (rho l)/(A)`, `R_(2) (rho 4l)/(A//4) = (16 rho l)/(A) = 16 R_(1)`
`P_(2) = (e_(2)^(2))/(R_(2)) = ((4e_(1))^(2))/(16R_(1)) = (e_(1)^(2))/(R_(1)) = P_(1)`
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