Home
Class 12
PHYSICS
In a series LCR circuit, voltage drop ax...

In a series LCR circuit, voltage drop axross L can be more than applied voltage (True/false).

Text Solution

AI Generated Solution

To determine whether the statement "In a series LCR circuit, the voltage drop across L can be more than the applied voltage" is true or false, we can analyze the circuit step by step. ### Step-by-Step Solution: 1. **Understanding the Circuit**: - In a series LCR circuit, we have an inductor (L), a capacitor (C), and a resistor (R) connected in series to an AC voltage source. The total voltage applied across the circuit is denoted as \( V \). 2. **Voltage Drops in the Circuit**: ...
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Exercises Subjective|15 Videos

  • ALTERNATING CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Exercises Single Correct|63 Videos

  • ALTERNATING CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|6 Videos

  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise ddp.4.3|15 Videos

Similar Questions

Explore conceptually related problems

In series LCR circuit, the voltages across R, L and C are shown in the figure. The voltage of applied source

In a series LR circuit, the voltage drop across inductor is 8 volt and across resistor is 6 volt. Then voltage applied and power factor of circuit respectively are:

In series LCR AC circuit, the voltage of the source at any instant is equal to

In series LCR circuit, the phase angle between supply voltage and current is

In a series LCR circuit, the voltages across an inductor, a capacitor and a resistor are 30 V, 30 V, 60 V respectively. What is the phase difference between the applied voltage and the current in the circuit ?

In a series LCR circuit, the voltages across an inductor, a capacitor and a resistor are 30 V, 30 V, 60 V respectively. What is the phase difference between the applied voltage and the current in the circuit ?

In a series LCR circuit, the voltage across the resistance, capacitance and inductance is 10 V each. If the capacitance is short circuited, the voltage across the inductance will be

Assertion: In series, L-C-R voltage across capacitor is always less than the applied voltage. Reason: In series L-C-R circuit, V = sqrt((V_R^(2) + (V_(L)^(2)-V_(C)^(2)))

In a series LCR circuit the rms voltage across the inductance , capacitance and resistance are respectively 4 V, 8 V and 5 V . The RMS voltage of the AC source in the circuit is

In a series L-C-R circuit, currenrt in the circuit is 11A when the applied voltage is 220 V . voltage across the caspcitor is 200 V . If the value of resistor is 20 Omega , then the voltage across the unknown inductor is