Find the result of mixing 0.5 kg ice at `0^@C` with 2 kg water at `30^@C`. Given that latent heat of ice is `L=3.36xx10^5 J//kg` and specific heat of water is `4200 J//kg//K`.

Explanation

To solve the problem of mixing 0.5 kg of ice at 0°C with 2 kg of water at 30°C, we will follow these steps:

### Step 1: Calculate the heat required to melt the ice
The heat required to completely melt the ice can be calculated using the formula:
\[ Q_{\text{melt}} = m_{\text{ice}} \times L \]
where:
- \( m_{\text{ice}} = 0.5 \, \text{kg} \)
- \( L = 3.36 \times 10^5 \, \text{J/kg} \)
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