A beaker contains 200 g of water. The he...

A beaker contains 200 g of water. The heat capacity of the beaker is equal to that of 20 g of water. The initial temperature of water in the beaker is `20^@C` .If 440 g of hot water at `92^@C` is poured in it, the final temperature (neglecting radiation loss) will be nearest to

`58^@C`

`68^@C`

`73^@C`

`78^@C`

Text Solution

Verified by Experts

The correct Answer is:

Heat lost by hot water`=`heat gained by cold water in beaker`+`heat absorbed by beaker
`implies440(92-T)=200xx(T-20)+20xx(T-20)`
`impliesT=68^@C`

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