A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2 c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

Options

A. `(2//3)T`
B. `(8//5)T`
C. `(3//5)T`
D. `(3//2)T`

Answer

D

Explanation

Temperature of mixture is given by
`T=(m_1c_1T_1+m_2c_2T_2)/(m_1c_1+m_2c_2)=(mc2T+(m)/(2)2cT)/(mc+(m)/(2)2c)=(3)/(2)T`