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A black body at 200 K is found to emit m...

A black body at 200 K is found to emit maximum energy at a wavelength of `14mu m`. When its temperature is raised to 1000 K, the wavelength at which maximum energy is emitted is

A

`14mum`.

B

`70mum`.

C

`2.8mum`

D

`2.8mum`.

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The correct Answer is:
To solve the problem, we will use Wien's Displacement Law, which states that the product of the wavelength at which maximum energy is emitted (λm) and the absolute temperature (T) of a black body is a constant. ### Step-by-Step Solution: 1. **Identify the Given Values**: - Initial Temperature (T1) = 200 K - Wavelength corresponding to T1 (λm1) = 14 μm - Final Temperature (T2) = 1000 K - Wavelength corresponding to T2 (λm2) = ? 2. **Apply Wien's Displacement Law**: According to Wien's Displacement Law: \[ λm \cdot T = \text{constant} \] Therefore, we can write: \[ λm1 \cdot T1 = λm2 \cdot T2 \] 3. **Substitute the Known Values**: Substitute the values we have into the equation: \[ 14 \, \mu m \cdot 200 \, K = λm2 \cdot 1000 \, K \] 4. **Rearrange the Equation to Solve for λm2**: Rearranging gives us: \[ λm2 = \frac{14 \, \mu m \cdot 200 \, K}{1000 \, K} \] 5. **Calculate λm2**: Now perform the calculation: \[ λm2 = \frac{2800 \, \mu m \cdot K}{1000 \, K} = 2.8 \, \mu m \] 6. **Final Answer**: The wavelength at which maximum energy is emitted when the temperature is raised to 1000 K is: \[ λm2 = 2.8 \, \mu m \] ### Summary: The wavelength at which maximum energy is emitted when the temperature is raised to 1000 K is **2.8 μm**.

To solve the problem, we will use Wien's Displacement Law, which states that the product of the wavelength at which maximum energy is emitted (λm) and the absolute temperature (T) of a black body is a constant. ### Step-by-Step Solution: 1. **Identify the Given Values**: - Initial Temperature (T1) = 200 K - Wavelength corresponding to T1 (λm1) = 14 μm - Final Temperature (T2) = 1000 K ...
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