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A black body radiates poer P and maximum...

A black body radiates poer P and maximum energy is radiated by it around a wavelength `lambda_(0)`. The temperature of the black body is now changed such that it radiates maximum energy around the wavelength `(3lambda_(0))/4`. The power radiated by it now is

A

`256//81`

B

`64//27`

C

`16//9`

D

`(4)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

According to Wien's law, wavelength corresponding to maximum energy decreases. When the temperature of black body increases i.e., `lamda_mT=` constant
`implies=(T_2)/(T_1)=(lamda_1)/(lamda_2)=(lamda_0)/((3lamda_0)/(4))=(4)/(3)`
Now according to Stefan's law
`(E_2)/(E_1)=((T_2)/(T_1))^4=((4)/(3))^4=(256)/(81)`
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