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The coefficient of apparent expansion of...

The coefficient of apparent expansion of mercury in a glass vessel is `153xx10^(-6)//^(@)C` and in a steel vessel is `114xx10^(-6)//^(@)C`. If `alpha` for steel is `12xx10^(-6)//^(@)C`, then that of glass is

A

`9xx10^(-6)//^(@)C`

B

`6xx10^(-6)//^(@)C`

C

`36xx10^(-6)//^(@)C`

D

`27xx(10^(-6)//^(@)C`

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To find the coefficient of linear expansion of glass (α_glass), we can use the relationship between the coefficients of apparent expansion of mercury in different vessels and the coefficients of linear expansion of the vessels themselves. ### Step-by-Step Solution: 1. **Understanding the Apparent Expansion**: The coefficient of apparent expansion (β) of a liquid in a vessel is given by the formula: \[ \beta = \alpha_{liquid} - \alpha_{vessel} \] where: - \(\beta\) is the coefficient of apparent expansion, - \(\alpha_{liquid}\) is the coefficient of linear expansion of the liquid, - \(\alpha_{vessel}\) is the coefficient of linear expansion of the vessel. 2. **Setting Up the Equations**: For mercury in a glass vessel: \[ \beta_{glass} = \alpha_{mercury} - \alpha_{glass} \] For mercury in a steel vessel: \[ \beta_{steel} = \alpha_{mercury} - \alpha_{steel} \] 3. **Substituting the Given Values**: Given: - \(\beta_{glass} = 153 \times 10^{-6} \, ^(@)C\) - \(\beta_{steel} = 114 \times 10^{-6} \, ^(@)C\) - \(\alpha_{steel} = 12 \times 10^{-6} \, ^(@)C\) From the second equation: \[ 114 \times 10^{-6} = \alpha_{mercury} - 12 \times 10^{-6} \] Rearranging gives: \[ \alpha_{mercury} = 114 \times 10^{-6} + 12 \times 10^{-6} = 126 \times 10^{-6} \, ^(@)C \] 4. **Finding α_glass**: Now substitute \(\alpha_{mercury}\) into the first equation: \[ 153 \times 10^{-6} = 126 \times 10^{-6} - \alpha_{glass} \] Rearranging gives: \[ \alpha_{glass} = 126 \times 10^{-6} - 153 \times 10^{-6} \] \[ \alpha_{glass} = -27 \times 10^{-6} \, ^(@)C \] 5. **Calculating the Linear Expansion Coefficient**: Since we are looking for the volumetric expansion coefficient, we can use the relationship: \[ \alpha_{glass} = \frac{1}{3} \times (-27 \times 10^{-6}) = -9 \times 10^{-6} \, ^(@)C \] ### Final Answer: The coefficient of linear expansion of glass (α_glass) is: \[ \alpha_{glass} = -9 \times 10^{-6} \, ^(@)C \]

To find the coefficient of linear expansion of glass (α_glass), we can use the relationship between the coefficients of apparent expansion of mercury in different vessels and the coefficients of linear expansion of the vessels themselves. ### Step-by-Step Solution: 1. **Understanding the Apparent Expansion**: The coefficient of apparent expansion (β) of a liquid in a vessel is given by the formula: \[ \beta = \alpha_{liquid} - \alpha_{vessel} ...
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