A body cools from 50^@C to 49.9^@C in 5 ...

A body cools from `50^@C` to `49.9^@C` in 5 s. How long will it take to cool from `40^@C` to `39.9^@C`? Assume the temperature of surroundings to be `30^@C` and Newton's law of cooling to be valid:

2.5 s

10 s

20 s

5 s

Text Solution

Verified by Experts

The correct Answer is:

According to Newton's law of cooling, the ratio of cooling is directly proportional to the temperature difference. When the average temperature difference is halved the rate of cooling is also halved. So, the time taken is 10 s.

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