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The radiation emitted by a star A is 100...

The radiation emitted by a star `A` is `10000` times that of the sun. If the surface temperature of the sun and star `A` are `6000 K` and `2000 K` respectively. The ratio of the radii of the star `A` and the sun is:

A

`300:1`

B

`600:1`

C

`900:1`

D

`1200:1`

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The correct Answer is:
To solve the problem, we will use the Stefan-Boltzmann law, which states that the energy radiated per second by a black body is proportional to the fourth power of its absolute temperature. ### Step-by-step Solution: 1. **Understand the Given Information**: - Radiation emitted by star A (E1) is 10,000 times that of the Sun (E2). - Surface temperature of the Sun (T2) = 6000 K. - Surface temperature of star A (T1) = 2000 K. 2. **Apply the Stefan-Boltzmann Law**: The energy radiated per second (E) is given by: \[ E = \sigma A T^4 \] where \(A\) is the surface area and \(\sigma\) is the Stefan-Boltzmann constant. 3. **Express the Areas**: The surface area of a sphere is given by \(A = 4\pi R^2\). Thus, for star A and the Sun: - \(A_1 = 4\pi R_1^2\) (for star A) - \(A_2 = 4\pi R_2^2\) (for the Sun) 4. **Set Up the Ratio of Energy Emitted**: According to the problem, we have: \[ E_1 = 10,000 \times E_2 \] Substituting the expressions for energy: \[ \sigma A_1 T_1^4 = 10,000 \times \sigma A_2 T_2^4 \] The \(\sigma\) cancels out: \[ A_1 T_1^4 = 10,000 \times A_2 T_2^4 \] 5. **Substituting Areas**: Substitute \(A_1\) and \(A_2\): \[ (4\pi R_1^2) T_1^4 = 10,000 \times (4\pi R_2^2) T_2^4 \] The \(4\pi\) cancels out: \[ R_1^2 T_1^4 = 10,000 \times R_2^2 T_2^4 \] 6. **Rearranging the Equation**: Rearranging gives: \[ \frac{R_1^2}{R_2^2} = 10,000 \times \frac{T_2^4}{T_1^4} \] 7. **Substituting the Temperatures**: Substitute \(T_1 = 2000 K\) and \(T_2 = 6000 K\): \[ \frac{R_1^2}{R_2^2} = 10,000 \times \left(\frac{6000}{2000}\right)^4 \] Simplifying \(\frac{6000}{2000} = 3\): \[ \frac{R_1^2}{R_2^2} = 10,000 \times 3^4 \] 8. **Calculating \(3^4\)**: \[ 3^4 = 81 \] Thus: \[ \frac{R_1^2}{R_2^2} = 10,000 \times 81 = 810,000 \] 9. **Taking the Square Root**: \[ \frac{R_1}{R_2} = \sqrt{810,000} = 900 \] 10. **Final Ratio**: Therefore, the ratio of the radii of star A to the Sun is: \[ R_1 : R_2 = 900 : 1 \]

To solve the problem, we will use the Stefan-Boltzmann law, which states that the energy radiated per second by a black body is proportional to the fourth power of its absolute temperature. ### Step-by-step Solution: 1. **Understand the Given Information**: - Radiation emitted by star A (E1) is 10,000 times that of the Sun (E2). - Surface temperature of the Sun (T2) = 6000 K. - Surface temperature of star A (T1) = 2000 K. ...
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