A partical excutes SHM with an angular frequency `omega = 4 pi rad//s`. If it is at its extereme position initially, then find the transition when it is at a distance `sqrt2//2` times its amplitude from the mean position.

Explanation

To solve the problem step by step, we will use the concepts of Simple Harmonic Motion (SHM).

### Step 1: Understand the parameters given
We are given:
- Angular frequency, \( \omega = 4\pi \, \text{rad/s} \)
- The particle starts at its extreme position, which means the initial displacement \( x(0) = A \) (where \( A \) is the amplitude).
- We need to find the time \( t \) when the particle is at a distance \( \frac{\sqrt{2}}{2} A \) from the mean position.

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