Home
Class 11
PHYSICS
A particle executes SHM with an amplitu...

A particle executes SHM with an amplitude `8 cm` and a frequency `4 Hz` initially, in the positive direction , determine its displacement equation and the maximum velocity and acceleration.

Text Solution

AI Generated Solution

To solve the problem step by step, we will determine the displacement equation for the particle executing Simple Harmonic Motion (SHM), and then find the maximum velocity and acceleration. ### Step 1: Identify the given parameters - Amplitude (A) = 8 cm = 0.08 m (convert to meters) - Frequency (f) = 4 Hz ### Step 2: Calculate angular frequency (ω) The angular frequency (ω) is related to the frequency (f) by the formula: ...
Promotional Banner

Topper's Solved these Questions

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Solved Example|15 Videos

  • LINEAR AND ANGULAR SIMPLE HARMONIC MOTION

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 4.1|23 Videos

  • KINETIC THEORY OF GASES AND FIRST LAW OF THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger|11 Videos

  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger type|3 Videos

Similar Questions

Explore conceptually related problems

A particle executing S.H.M. having amplitude 0.01 m and frequency 60 Hz. Determine maximum acceleration of particle.

A particle executes SHM with frequency 4 Hz. Frequency with which its PE oscillates is

Two particles execute SHM of same amplitude and frequency on parallel lines. They pass one another when moving in opposite directions each time their displacement is one third their amplitude. What is the phase difference between them?

A particle executes SHM with an amplitude of 10 cm and frequency 2 Hz , at t = 0 , the particle is at point where potential energy and kinetic energy are same. Find the equation of displacement of particle.

Two particles execute SHM of same amplitude and frequency on parallel lines. They pass one another when moving in opposite directions each time their displacement is half of their amplitude. What is the phase difference between them?

A particle executes shm with an amplitude of 10 cm and a period of 5 s. Find the velocity and acceleration of the particle of a distance 5 cm from the equilibrium position.

A particle is executing SHM with an amplitude 4 cm. the displacment at which its energy is half kinetic and half potential is

A particle executing simple harmonic motion with an amplitude A and angularr frequency omega . The ratio of maximum acceleration to the maximum velocity of the particle is

A particle is executing SHM with amplitude 4 cm and has a maximum velocity of 10 cm/sec What is its velocity at displacement 4 cm/sec ?

A particle executing SHM of amplitude 4 cm and T=4 s .The time taken by it to move from positive extreme position to half the amplitude is