A particle of mass `m = 1 kg` oscillates simple harmonically with angular frequency `1 rad//s`. Find the phase of the particle at `t = 1 s and 2 s`. Start calculating time when the particle moves up passing through the mean position.

Explanation

To solve the problem step by step, we will follow the principles of simple harmonic motion (SHM) and the given parameters.

### Step-by-Step Solution:

1. **Understand the Problem**: We have a particle of mass \( m = 1 \, \text{kg} \) that oscillates with an angular frequency \( \omega = 1 \, \text{rad/s} \). We need to find the phase of the particle at \( t = 1 \, \text{s} \) and \( t = 2 \, \text{s} \), starting from when the particle is at the mean position (displacement \( x = 0 \)).

2. **Displacement Equation**: The displacement \( x \) of a particle in SHM can be described by the equation:
\[
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