If `x = A//2` at `t = 0`, Find phase constant `(alpha)` in `x = A sin (omega t + alpha)`, at `t = 0`, a particle executing SHM is going along negative x axis

Explanation

To find the phase constant \( \alpha \) in the equation \( x = A \sin(\omega t + \alpha) \) given that \( x = \frac{A}{2} \) at \( t = 0 \) and the particle is moving along the negative x-axis, we can follow these steps:

### Step-by-Step Solution:

1. **Substitute the given values into the equation**:
At \( t = 0 \), we have:
\[
x = A \sin(\omega \cdot 0 + \alpha) = A \sin(\alpha)
...