two partical excuting SHM with same frequency and amplitudes `A and 2A` on same straight line with same mean position cross each other in opposite direction at a distance `A//3` from mean possion. Find the phase difference in the two SHM s.

Explanation

To solve the problem of finding the phase difference between two particles executing Simple Harmonic Motion (SHM), we will follow these steps:

### Step 1: Define the equations of motion for both particles
Let the first particle have an amplitude \( A \) and the second particle have an amplitude \( 2A \). The equations of motion can be written as:
- For particle 1:
\[ x_1 = A \sin(\omega t + \theta_1) \]
...