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Two particle A and B execute simple harm...

Two particle `A and B` execute simple harmonic motion according to the equation `y_(1) = 3 sin omega t` and `y_(2) = 4 sin [omega t + (pi//2)] + 3 sin omega t`. Find the phase difference between them.

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To find the phase difference between the two particles A and B executing simple harmonic motion (SHM), we will follow these steps: ### Step 1: Write down the equations of motion The equations for the two particles are given as: - Particle A: \( y_1 = 3 \sin(\omega t) \) - Particle B: \( y_2 = 4 \sin\left(\omega t + \frac{\pi}{2}\right) + 3 \sin(\omega t) \) ### Step 2: Simplify the equation for Particle B ...
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