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A block of mass m hangs by means of a st...

A block of mass m hangs by means of a string which goes over a pulley of mass m and moment of inertia l, as shown in the diagram. The string does not realtive to the pulley. Find the frequency of small oscillations.

Text Solution

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Suppose the block is depresed by x. The pulley (owing to the constant) is depresed by `x//2`. Suppose the tension in the string are T and T' on both sides . We can write

for block `mg - T = mx` (i)
For pulley, `T + T' + mg - k (x + x_(0)) = m (x)/(2)` (ii)
The angular acceleration of the pulley ,
`alpha = (x//2)/(2 R)` (iii)
`(T - T' ) R = l (x)/(2 R)` (iv)
From the Eqs. (i), (ii), (iii) and (iv), we get
`3 mg - k (x + x_(0)) = ((5 m)/(2) + (l)/(2 R^(2))) x`
The frequency of small oscllation
`f = (1)/(2 pi) sqrt((k)/((5m)/(2) + (l)/(2 R^(2)))`
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