A partical in SHM ha a period of 4s .It takes time `t_(1)` to start from mean position and reach half the amplitude. In another case it taken a time `t_(2)` to start from extreme position and reach half the amplitude. Find the ratio `t_(1)//t_(2)`

Explanation

To solve the problem, we need to find the ratio \( \frac{t_1}{t_2} \), where \( t_1 \) is the time taken to go from the mean position to half the amplitude, and \( t_2 \) is the time taken to go from the extreme position to half the amplitude. The period \( T \) of the simple harmonic motion (SHM) is given as 4 seconds.

### Step 1: Determine \( t_1 \)

1. The displacement \( x \) in SHM can be expressed as:
\[ x = A \sin(\omega t) \]
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