`x_(1) = 5 sin omega t`
` x_(2) = 5 sin (omega t + 53^(@))`
`x_(3) = - 10 cos omega t`
Find amplitude of resultant SHM.

Explanation

To find the amplitude of the resultant Simple Harmonic Motion (SHM) given the equations \( x_1 = 5 \sin(\omega t) \), \( x_2 = 5 \sin(\omega t + 53^\circ) \), and \( x_3 = -10 \cos(\omega t) \), we will follow these steps:

### Step 1: Rewrite \( x_3 \)
We can rewrite \( x_3 \) in terms of sine:
\[ x_3 = -10 \cos(\omega t) = -10 \sin\left(\omega t + \frac{\pi}{2}\right) \]

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