A body is in `SHM` with period `T` when oscillated from a freely suspended spring. If this spring is cut in two parts of length ratio `1 : 3 &` again oscillated from the two the two parts separatedly, then the periods are `T_(1) & T_(2)` then find `T_(1)//T_(2)`.

Explanation

To solve the problem, we need to understand the relationship between the period of oscillation of a spring and its properties. The period \( T \) of a mass-spring system in simple harmonic motion (SHM) is given by the formula:

\[ T = 2\pi \sqrt{\frac{m}{k}} \]

where \( m \) is the mass attached to the spring and \( k \) is the spring constant.

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