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In the arrangement shown in figure the s...

In the arrangement shown in figure the sleeve `M` of mass `m=0.20kg ` is fixed between two identical springs whose combined stiffness is equal to `x=20 N//m`. The sleeve can slide without friction over a horizontal bar `AB`. The arrrangement rotates with a constant angular velocity `omega=4.4 rad//s` about a vertical axis passing through the middle of the bar . Find the period of small oscillations of the sleeve. At what values of `omega` will there be no oscillations of the sleeve ?

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Verified by Experts

The correct Answer is:
`2 pi sqrt((m)/(k - m omega^(2)))`

We will analyse se the problem relative to the rotating bar AB. As the acceleration of bar is centripetaing , a pseudo force will act on sleeve away from the centre and will be of magnitude `m (omega^(2) x)`.
If the sleves is displaced by x, net force towards center

`F = kx - m omega^(2) x = (m - m omega^(2)) x`
`implies period = 2 pi sqrt((m)/(k - m omega^(2)))`
Note that if `k lt m omega^(2)`. there will be no oscillations of the sleves. It will rush to the point B if it is displaced slightly (for `k lt m omega^(2))`. or will remain in the displaced position `(for k = m omega^(2))`.
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