A block A is connected to spring and performs simple harmonic motion with a time period of 2 s. Another block B restes on a. The coefficient of static friction between `A` and `B` is `mu_S=0.6`. The maximum amplitude of oscillation which the system can have so that there is no relative motion between A and B is (take `pi^2=g=10`)

Options

A. (a)0.3 m
B. (b)0.6 m
C. (c)0.4 m
D. (d)0.52 m

Answer

B

Explanation

Let A be the maximum amplitude of oscillation for the required situation. Then `f=momega^2x` (from free body diagram of blocks)
For required condition `f=momega^2A`
i.e., `momega^2Altmu_(S)mg`
`impliesAlt(0.6xxg)/((4pi^2)/(4))=0.6mimpliesA_(max)=0.6m`