The osciallations represented by curve 1 in the graph are expressed by equation `x=A sinepsilont`. The equation for the oscillations represented by curve 2 is expressed as

Options

A. `x=2Asin(omegat-(pi)/(2))`
B. `x=2Asin(omegat+(pi)/(2))`
C. `x=-2Asin(omegat-(pi)/(2))`
D. `x=Asin(omegat-(pi)/(2))`

Answer

A

Explanation

Oscillations represented by curve 2 lags in phase by `(pi)/(2)` and the periods are same. Amplitude of curve 2 is double that of 1. Put `t=0` then `x=2Asin(0-(pi)/(2))=-2A`