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For a simple harmonic motion with given ...

For a simple harmonic motion with given angular frequency `omega`, two arbitrary initial conditions are necessary and sufficient to determine the motion completely. These initial conditions may be

A

initial position and initial velocity

B

amplitude and initial phase

C

total energy of oscillation and amplitude

D

total energy of oscillation and initial phase.

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To determine the complete motion of a simple harmonic oscillator with a given angular frequency \( \omega \), we need two arbitrary initial conditions. Here’s a step-by-step solution to identify the necessary conditions: ### Step 1: Understanding Simple Harmonic Motion (SHM) The general equation for simple harmonic motion can be expressed as: \[ x(t) = A \cos(\omega t + \delta) \] where: - \( x(t) \) is the displacement at time \( t \), - \( A \) is the amplitude, - \( \omega \) is the angular frequency, - \( \delta \) is the phase constant. ### Step 2: Identifying Initial Conditions To fully describe the motion, we need to determine both the amplitude \( A \) and the phase constant \( \delta \). This can be achieved through various combinations of initial conditions. ### Step 3: Analyzing Possible Initial Conditions 1. **Initial Position and Initial Velocity**: - Knowing the initial position \( x(0) \) and initial velocity \( v(0) \) allows us to solve for both \( A \) and \( \delta \). 2. **Amplitude and Initial Phase**: - If we know the amplitude \( A \) and the phase \( \delta \), we can describe the motion completely. 3. **Total Energy of Oscillation and Amplitude**: - The total energy \( E \) in SHM is given by: \[ E = \frac{1}{2} k A^2 \] Knowing \( E \) and \( A \) does not provide enough information to determine \( \delta \). 4. **Total Energy of Oscillation and Initial Phase**: - Knowing \( E \) and \( \delta \) allows us to find \( A \) using the energy formula, thus giving us a complete description of the motion. ### Step 4: Conclusion From the analysis, the combinations of initial conditions that are sufficient to determine the motion completely are: - Initial Position and Initial Velocity (Option A) - Amplitude and Initial Phase (Option B) - Total Energy of Oscillation and Initial Phase (Option D) The combination of Total Energy of Oscillation and Amplitude (Option C) does not provide sufficient information to determine the phase constant \( \delta \). ### Final Answer The initial conditions that are necessary and sufficient to determine the motion completely are: - **Option A**: Initial Position and Initial Velocity - **Option B**: Amplitude and Initial Phase - **Option D**: Total Energy of Oscillation and Initial Phase

To determine the complete motion of a simple harmonic oscillator with a given angular frequency \( \omega \), we need two arbitrary initial conditions. Here’s a step-by-step solution to identify the necessary conditions: ### Step 1: Understanding Simple Harmonic Motion (SHM) The general equation for simple harmonic motion can be expressed as: \[ x(t) = A \cos(\omega t + \delta) \] where: ...
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CENGAGE PHYSICS ENGLISH-LINEAR AND ANGULAR SIMPLE HARMONIC MOTION-Multiple Correct
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  2. For a simple harmonic motion with given angular frequency omega, two a...

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  3. The potential energy U of a body of unit mass moving in one dimensiona...

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  4. For the spring pendulum shown in fig. the value of spring constant is ...

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  5. An object of mass m is performing simple harmonic motion on a smooth h...

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  6. A simple pendulum consists of a bob of mass m and a light string of le...

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  7. A particle performing simple harmonic motion undergoes unitial displac...

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  8. A particle is subjected to two simple harmonic motions along x and y d...

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  9. The speed of a particle moving along a straight line, when it is at a ...

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  10. A horizontal plank has a rectangular block placed on it. The plank sta...

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  11. A 20g particle is subjected to two simple harmonic motions x1=2sin10t,...

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  12. A spring block system undergoes SHM on a smooth horizontal surface, th...

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  13. The potential energy of a particle of mass 0.1 kg , moving along the X...

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  14. The time period of a particle in simple harmonic motion is T. Assume p...

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  15. Figure. (a) shows a spring of force constant k fixed at one end and ca...

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  16. When the point of suspendion of pendulum is moved, its period of oscil...

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  17. The displacement time relation for a particle can be expressed as y=0....

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  18. At two particular closest instant of time t1 and t2 the displacements ...

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  19. Two blocks connected by a spring rest on a smooth horizontal plane as ...

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  20. A block of mass m is suspended by a rubber cord of natural length l=(m...

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