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The displacement (x) of a particle as a ...

The displacement (x) of a particle as a function of time (t) is given by
`x=asin(bt+c)`
Where a,b and c are constant of motion. Choose the correct statemetns from the following.

A

The motion repeats itself in a time interval of `(2pi)/(b)`

B

The energy of the particle remains constant.

C

The velocity of the particle zero at `x=+-a`

D

The acceleration of the particle is zero at `x=+-a`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the given displacement function of a particle in simple harmonic motion (SHM), which is represented as: \[ x = a \sin(bt + c) \] Where: - \( a \) is the amplitude, - \( b \) is the angular frequency, - \( c \) is the phase constant. Now, let's evaluate each of the statements provided in the question. ### Step 1: Evaluate the first statement **Statement A:** The motion repeats itself in a time interval of \( \frac{2\pi}{b} \). **Solution:** In SHM, the period \( T \) is the time taken for one complete cycle of motion. The angular frequency \( b \) relates to the period by the formula: \[ T = \frac{2\pi}{b} \] Thus, the motion indeed repeats itself every \( \frac{2\pi}{b} \) seconds. Therefore, **Statement A is correct**. ### Step 2: Evaluate the second statement **Statement B:** The energy of the particle remains constant. **Solution:** In SHM, the total mechanical energy (E) is conserved and is given by: \[ E = \frac{1}{2} k A^2 \] Where \( k \) is the spring constant and \( A \) is the amplitude. Since there are no non-conservative forces doing work (like friction), the energy remains constant throughout the motion. Hence, **Statement B is correct**. ### Step 3: Evaluate the third statement **Statement C:** The velocity of the particle is zero at \( x = \pm a \). **Solution:** In SHM, the velocity \( v \) is given by the derivative of displacement with respect to time: \[ v = \frac{dx}{dt} = a b \cos(bt + c) \] The velocity is zero when the displacement is at its maximum or minimum, which occurs at \( x = \pm a \). Therefore, **Statement C is correct**. ### Step 4: Evaluate the fourth statement **Statement D:** The acceleration of the particle is zero at \( x = \pm a \). **Solution:** The acceleration \( a \) in SHM is given by: \[ a = -\omega^2 x \] Where \( \omega = b \). At \( x = \pm a \), the acceleration is: \[ a = -b^2(\pm a) \] This means the acceleration is at its maximum magnitude (not zero) at the extreme positions \( x = \pm a \). Therefore, **Statement D is incorrect**. ### Conclusion: The correct statements are A, B, and C. ### Final Answer: The correct statements are: - Statement A: Correct - Statement B: Correct - Statement C: Correct - Statement D: Incorrect

To solve the question, we need to analyze the given displacement function of a particle in simple harmonic motion (SHM), which is represented as: \[ x = a \sin(bt + c) \] Where: - \( a \) is the amplitude, - \( b \) is the angular frequency, - \( c \) is the phase constant. ...
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