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A 100 g block is connected to a horizont...


A 100 g block is connected to a horizontal massless spring of force constant `25.6(N)/(m)` As shown in Fig. the block is free to oscillate on a horizontal frictionless surface. The block is displaced 3 cm from the equilibrium position and , at `t=0`, it is released from rest at `x=0` It executes simple harmonic motion with the postive x-direction indecated in Fig. The position time `(x-t)` graph of motion of the block is as shown in Fig.
Velocity of the block as a function of time can be expressed as

A

`v=-sin48(16t(pi)/(2))(cm)/(s)`

B

`v=-48sin(16t(pi)/(3))(cm)/(s)`

C

`v=-56sin(16t(pi)/(4))(cm)/(s)`

D

`v=-56(16t(pi)/(6))(cm)/(s)`

Text Solution

Verified by Experts

The correct Answer is:
D

Differentiating previous result
`v=-31sqrt3sin(16t+(pi)/(6))(cm)/(s)`
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