A wave is travelling along X-axit. The disturbance at x=0 and t=0 is `A//2` and is increasing. Where A is amplitute of the wave. If `y=A sin(kx-omegat+emptyset)`, deetemine the initial phase `empyset`.

Explanation

To determine the initial phase \( \phi \) of the wave described by the equation \( y = A \sin(kx - \omega t + \phi) \), we follow these steps:

### Step 1: Substitute Initial Conditions
We know that at \( x = 0 \) and \( t = 0 \), the disturbance \( y \) is given as \( \frac{A}{2} \). Substituting these values into the wave equation gives us:
\[ y = A \sin(k \cdot 0 - \omega \cdot 0 + \phi) = A \sin(\phi) \]
Thus, we have:
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