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A piano wire with mass 3.00 g and length...

A piano wire with mass 3.00 g and length 80.0 cm is stretched with a tension of 25.0 N. A wave with frequancy 120.0 Hz and amplitude 1.6 mm travels along the wire. (a) calculate the average power carried by the wave. (b) what happenes to the avarage power if the wave amplitude is halved?

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(a). As we know `P_(ave)=(1)/(2)(sqrtmuF)omega^(2)A^(2)`
=(1)/(2)[sqrt{(3.00xx10^(-3) kg)/(0.80 m)(25.0 N))][(2pi(120.0 Hz)]^(2)(1.6xx10^(-3))^(2)`
`=0.223 W`
(b). Halving the amplitude quarters the average power, so `0.056 W`.
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