A transverse harmonic wave of amplitude 0.01 m is genrated at one end (x=0) of a long horizontal string by a tuning fork of frequency 500 Hz. At a given instant of time the displacement of the particle at x=0.1 m is -0.005 m and that of the particle at x=0.2 m is +0.005 m. calculate the wavelength and the wave velocity. obtain the equetion of the wave assuming that the wave is traveling along the + x-direction and that the end x=0 is at he equilibrium position at t=0.

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Understand the given information
- Amplitude \( A = 0.01 \, \text{m} \)
- Frequency \( f = 500 \, \text{Hz} \)
- Displacement at \( x = 0.1 \, \text{m} \) is \( y(0.1) = -0.005 \, \text{m} \)
- Displacement at \( x = 0.2 \, \text{m} \) is \( y(0.2) = +0.005 \, \text{m} \)

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