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The equation of a transverse wave travel...

The equation of a transverse wave travelling on a rope given by `y=10sinpi(0.01x-2.00t)` whrer y and x are in cm and t in second .This maximum traverse speed of a particle in the rope is about

A

`63 cm//s`

B

`75 cm//s`

C

`100 cm//s`

D

` 121 cm//s`

Text Solution

Verified by Experts

The correct Answer is:
a
Standard equation of travelling wave `y=A sin(kx-omegat)` by comparing with the given equation `y=10 sin (0.01pix-2pit)`
`A=10 cm,omega=2pi`
maximum particle velocity `=Aomega=2pixx10=63 cm//s`
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