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The path difference between the two wave...

The path difference between the two waves
`y_(1)=a_(1) sin(omega t-(2pi x)/(lambda)) and y(2)=a_(2) cos(omega t-(2pi x)/(lambda)+phi)` is

A

`(lambda)/(2pi)/phi`

B

`(lambda)/(2pi)(phi+(pi)/(2))`

C

`(2pi)/(lambda)(phi-(pi)/(2))`

D

`(2pi)/(lambda)(phi)`

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To find the path difference between the two waves given by the equations: 1. \( y_1 = A_1 \sin\left(\omega t - \frac{2\pi x}{\lambda}\right) \) 2. \( y_2 = A_2 \cos\left(\omega t - \frac{2\pi x}{\lambda} + \phi\right) \) we can follow these steps: ### Step 1: Convert the cosine function to sine We know from trigonometric identities that: \[ \cos(\theta) = \sin\left(\theta + \frac{\pi}{2}\right) \] Thus, we can rewrite \( y_2 \): \[ y_2 = A_2 \cos\left(\omega t - \frac{2\pi x}{\lambda} + \phi\right) = A_2 \sin\left(\omega t - \frac{2\pi x}{\lambda} + \phi + \frac{\pi}{2}\right) \] ### Step 2: Identify the phase difference The phase of \( y_1 \) is: \[ \phi_1 = \omega t - \frac{2\pi x}{\lambda} \] The phase of \( y_2 \) is: \[ \phi_2 = \omega t - \frac{2\pi x}{\lambda} + \phi + \frac{\pi}{2} \] The phase difference \( \Delta \phi \) is given by: \[ \Delta \phi = \phi_2 - \phi_1 = \left(\omega t - \frac{2\pi x}{\lambda} + \phi + \frac{\pi}{2}\right) - \left(\omega t - \frac{2\pi x}{\lambda}\right) \] This simplifies to: \[ \Delta \phi = \phi + \frac{\pi}{2} \] ### Step 3: Calculate the path difference The path difference \( \Delta x \) can be calculated using the formula: \[ \Delta x = \frac{\lambda}{2\pi} \Delta \phi \] Substituting the expression for \( \Delta \phi \): \[ \Delta x = \frac{\lambda}{2\pi} \left(\phi + \frac{\pi}{2}\right) \] ### Step 4: Final expression for path difference Thus, we can express the path difference as: \[ \Delta x = \frac{\lambda}{2\pi} \phi + \frac{\lambda}{2\pi} \cdot \frac{\pi}{2} \] This simplifies to: \[ \Delta x = \frac{\lambda}{2\pi} \phi + \frac{\lambda}{4} \] Since \( \frac{\lambda}{4} \) is equivalent to \( \frac{\lambda}{2\pi} \cdot \frac{\pi}{2} \). ### Conclusion The final expression for the path difference is: \[ \Delta x = \frac{\lambda}{2\pi} \left(\phi + \frac{\pi}{2}\right) \]

To find the path difference between the two waves given by the equations: 1. \( y_1 = A_1 \sin\left(\omega t - \frac{2\pi x}{\lambda}\right) \) 2. \( y_2 = A_2 \cos\left(\omega t - \frac{2\pi x}{\lambda} + \phi\right) \) we can follow these steps: ### Step 1: Convert the cosine function to sine ...
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