A transverse wave is described by the equatiion `Y = Y_(0) sin 2pi (ft -x//lambda)`. The maximum particle velocity is equal to four times the wave velocity if
`lambda = pi Y_(0) //4`
`lambda = pi Y_(0)//2`
`lambda = pi Y_(0)`
`lambda = 2pi Y_(0)`

Options

A. `lambda=(piy_(0))/(4)`
B. `lambda=(piy_(0))/(2)`
C. `lambda=piy_(0)`
D. `lambda=2pi Y_(0)`

Answer

b

Explanation

maximum particle velocity `= 4 `wave velocity
`Aomega=4 flambda`
`y_(0)2pi f=4flambda`
`lambda=(piy_(0))/(2)`