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A point source of sound is placed in a n...

A point source of sound is placed in a non-absorbing medium two points A and B are at the distance of 1 m and 2 m, respectively, from the source. The ratio of amplitudes of waves at A to B is

A

`1:1`

B

`1:4`

C

`1:2`

D

`2:1`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of amplitudes of waves at points A and B, we can follow these steps: ### Step 1: Understand the relationship between intensity and distance The intensity (I) of sound from a point source is inversely proportional to the square of the distance (R) from the source. This can be expressed mathematically as: \[ I \propto \frac{1}{R^2} \] ### Step 2: Define the distances for points A and B Given: - Distance from the source to point A, \( R_1 = 1 \, \text{m} \) - Distance from the source to point B, \( R_2 = 2 \, \text{m} \) ### Step 3: Calculate the intensity ratio Using the relationship from Step 1, we can find the ratio of intensities at points A and B: \[ \frac{I_1}{I_2} = \frac{R_2^2}{R_1^2} \] Substituting the values: \[ \frac{I_1}{I_2} = \frac{(2)^2}{(1)^2} = \frac{4}{1} \] Thus, the intensity ratio \( \frac{I_1}{I_2} = 4:1 \). ### Step 4: Relate intensity to amplitude The intensity of a wave is directly proportional to the square of its amplitude (A). This can be expressed as: \[ I \propto A^2 \] Thus, we can write the ratio of intensities in terms of amplitudes: \[ \frac{I_1}{I_2} = \frac{A_1^2}{A_2^2} \] ### Step 5: Calculate the amplitude ratio From the intensity ratio calculated in Step 3, we can express the amplitude ratio: \[ \frac{A_1^2}{A_2^2} = \frac{4}{1} \] Taking the square root of both sides gives: \[ \frac{A_1}{A_2} = \sqrt{\frac{4}{1}} = 2 \] Thus, the ratio of amplitudes \( A_1 : A_2 = 2 : 1 \). ### Final Answer The ratio of amplitudes of waves at points A to B is: \[ \boxed{2:1} \] ---

To solve the problem of finding the ratio of amplitudes of waves at points A and B, we can follow these steps: ### Step 1: Understand the relationship between intensity and distance The intensity (I) of sound from a point source is inversely proportional to the square of the distance (R) from the source. This can be expressed mathematically as: \[ I \propto \frac{1}{R^2} \] ### Step 2: Define the distances for points A and B Given: ...
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