The phase difference between two waves.
`y_(1)= 10^(-6) sin{100 t + (x/50)+ 0.5}m`
`y_(2)= 10^(-6) sin{100 t + (x/50)}m`
where, x is expressed in metre and t is expressed in second , is approximately

Options

A. 1.07 rad
B. 2.07 rad
C. 0.5 rad
D. 1.5 rad

Answer

a

Explanation

`y_(1)=10^(-6)sin(100t+(x)/(50)+0.5)m`
`Y_(2)=10^(-2)cos(100t+(x)/(50))m`
`implies y_(2)=10^(-2)sin(100t+(x)/(50)+(pi)/(2))`
Phase difference`=(pi)/(2)-0.5`
`=1.07 rad`