A transverse sinusoidal wave of amplitude `a`, wavelength `lamda` and frequency `f` is travelling on a stretched string. The maximum speed of any point on the string is `v//10`, where `v` is the speed of propagation of the wave. If `a = 10^-3 m and v = 10 m//s`, then `lamda and f` are given by.

Options

A. `lambda=2pixx10^(-2)m`
B. `lambda=10^(-3)m`
C. `f 10^(3)//(2pi)Hz`
D. `f=10^(4) Hz`

Answer

a., c., d.

Explanation

`v_(max)=aomega=a(2pif)`
Given that `a(2pif)=(v)/(10)=(10)/(10)=1`
`f=(1)/(2pia)=(10^(3)/(2pi)Hz`
As `v=flambda`
or `lambda=(v)/(f)=(10)/(10^(3)//(2pi)=2pixx10^(2)m`