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Sound waves from a tuning fork placed at...

Sound waves from a tuning fork placed at a point `P` reach another point `Q` , by two separate paths `PRQ and PSQ` . When `PSQ` is greater than `PRQ by 11.5 cm` , there is silence at `Q` . When the difference is `23 cm` , the sound becomes loudest at `Q`, and when `34.5 cm` , there is silence , and so on . Explain this effect and calculate the frequency of the fork if the velocity of sound is taken to be `331.2 m//s`.

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To solve the problem, we need to analyze the situation of sound waves reaching point Q from point P through two different paths, PRQ and PSQ. The key points are the path differences and their effects on the sound intensity at point Q. ### Step-by-Step Solution: 1. **Understanding Path Differences**: - Let the path PRQ be represented as \( x_2 \) and the path PSQ as \( x_1 \). - The path difference is given by \( \Delta x = x_1 - x_2 \). ...
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