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Six antinodes are observed in the air co...

Six antinodes are observed in the air column when a standing wave forms in a Kundt's tube . What is the length of the air column if steel bar of ` 1 m` length is clamped at the middle .
The velocity of sound in steel is `5250 m//s` and in air `343 m//s`.

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To solve the problem, we need to find the length of the air column in the Kundt's tube when 6 antinodes are formed, given that a steel bar of length 1 m is clamped at the middle. ### Step-by-Step Solution: 1. **Understanding the Setup**: - The steel bar is clamped at the middle, which means it acts as a fixed point for the standing wave. This creates two segments of the bar, each of length 0.5 m. 2. **Wavelength in Steel**: - The wavelength of the sound in the steel can be calculated using the formula for the wave speed: \[ v_s = f \lambda_s \] - Here, \( v_s \) is the velocity of sound in steel (5250 m/s), and \( \lambda_s \) is the wavelength in steel. - Since the length of the steel bar is 1 m, and it has a node at the center, the wavelength in steel can be expressed as: \[ \lambda_s = 2 \times \text{Length of the bar} = 2 \times 1 = 2 \text{ m} \] 3. **Finding the Frequency**: - Using the relationship between the wave speed and wavelength, we can find the frequency: \[ f = \frac{v_s}{\lambda_s} = \frac{5250 \, \text{m/s}}{2 \, \text{m}} = 2625 \, \text{Hz} \] 4. **Wavelength in Air**: - The frequency of sound in air will be the same as in steel, so we can use the velocity of sound in air (343 m/s) to find the wavelength in air: \[ v_a = f \lambda_a \] - Rearranging gives: \[ \lambda_a = \frac{v_a}{f} = \frac{343 \, \text{m/s}}{2625 \, \text{Hz}} \approx 0.1305 \, \text{m} \] 5. **Length of the Air Column**: - We know that 6 antinodes correspond to 6 half wavelengths (since the distance between two consecutive antinodes is \( \frac{\lambda_a}{2} \)): \[ L_0 = 6 \times \frac{\lambda_a}{2} = 3 \lambda_a \] - Substituting the value of \( \lambda_a \): \[ L_0 = 3 \times 0.1305 \, \text{m} \approx 0.3915 \, \text{m} \approx 39.15 \, \text{cm} \] ### Final Answer: The length of the air column is approximately **39.15 cm**.

To solve the problem, we need to find the length of the air column in the Kundt's tube when 6 antinodes are formed, given that a steel bar of length 1 m is clamped at the middle. ### Step-by-Step Solution: 1. **Understanding the Setup**: - The steel bar is clamped at the middle, which means it acts as a fixed point for the standing wave. This creates two segments of the bar, each of length 0.5 m. 2. **Wavelength in Steel**: ...
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