Home
Class 11
PHYSICS
A sound wave of wavelength lambda trave...

A sound wave of wavelength ` lambda` travels towards the right horizontally with a velocity `V`. It strikes and reflects from a vertical plane surface , travelling at a speed `v` towards the left . The number of positive crests striking in a time interval of `3 s` on the wall is

A

`3(V + v)//lambda`

B

`3(V - v)//lambda`

C

`(V + v)// 3 lambda`

D

`(V - v)// 3 lambda`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of positive crests striking a vertical plane surface in a time interval of 3 seconds, we can follow these steps: ### Step 1: Understand the Problem We have a sound wave traveling towards a wall and reflecting off it. We need to find out how many positive crests (or waves) hit the wall in a given time period. ### Step 2: Identify Given Data - Wavelength of the sound wave: \( \lambda \) - Speed of the sound wave towards the wall: \( V \) - Speed of the sound wave after reflection: \( v \) - Time interval: \( t = 3 \, \text{s} \) ### Step 3: Calculate the Relative Velocity When the wave strikes the wall, it travels towards the wall with speed \( V \) and reflects back with speed \( v \). Therefore, the effective speed at which the wave approaches the wall is the sum of these two speeds: \[ \text{Relative velocity} = V + v \] ### Step 4: Calculate the Distance Traveled in 3 Seconds The total distance traveled by the wave in 3 seconds can be calculated using: \[ \text{Distance} = \text{Relative velocity} \times \text{Time} \] Substituting the values, we get: \[ \text{Distance} = (V + v) \times 3 \] ### Step 5: Calculate the Number of Waves The number of waves (or positive crests) striking the wall can be calculated by dividing the total distance traveled by the wavelength \( \lambda \): \[ \text{Number of waves} = \frac{\text{Distance}}{\lambda} = \frac{(V + v) \times 3}{\lambda} \] ### Final Answer Thus, the number of positive crests striking the wall in a time interval of 3 seconds is: \[ \text{Number of positive crests} = \frac{3(V + v)}{\lambda} \] ---

To solve the problem of finding the number of positive crests striking a vertical plane surface in a time interval of 3 seconds, we can follow these steps: ### Step 1: Understand the Problem We have a sound wave traveling towards a wall and reflecting off it. We need to find out how many positive crests (or waves) hit the wall in a given time period. ### Step 2: Identify Given Data - Wavelength of the sound wave: \( \lambda \) - Speed of the sound wave towards the wall: \( V \) ...
Promotional Banner

Topper's Solved these Questions

  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS ENGLISH|Exercise Multiple|26 Videos
  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS ENGLISH|Exercise Assertion - Reasoning|6 Videos
  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|24 Videos
  • SOUND WAVES AND DOPPLER EFFECT

    CENGAGE PHYSICS ENGLISH|Exercise Integer|16 Videos
  • THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise 24|1 Videos

Similar Questions

Explore conceptually related problems

A sound wave of frequency f travels horizontally to the right . It is teflected from a larger vertical plane surface moving to left with a speed v . the speed of sound in medium is c (a) The number of waves striking the surface per second is f(c + upsilon)/(c) (b) The wavelength of reflected wave is (c(c-upsilon))/(f(c+upsilon)) (c) The frequency of the reflected wave is f((c+upsilon))/((c+upsilon)) (d) The number of beats heard by a stationary listener to the left of the reflecting surface is (upsilon f)/(c - upsilon)

A sound wave of frequency n travels horizontally to the right with speed with speed c. It is reflected from a broad wall moving to the left with speed v. The number of beats heard by a stationary observer to the left of the wall is

A sound wave of frequency n travels horizontally to the right with speed with speed c. It is reflected from a broad wall moving to the left with speed v. The number of beats heard by a stationary observer to the left of the wall is

A source of sound of frequency 256 Hz moves rapidly towards a wall with a velocity of 5 ms^(-1). How many beats per second will be heard if sound travels at a speed of 330 m/s?

A sound source emits two sinusoidal sound waves, both of wavelength lambda , along paths A and B as shown in figure.The sound travelling along path B is reflected from five surfaces as shown and then merges at point Q, producing minimum intensity at that point.The minimum value of d in terms of lambda is :

In the figure shown, light waves A and B both of wavelength lambda are initially in phase and travelling rightward as incident by the two rays. Wave A is reflected from four parallel surfaces but ends up travelling in original direction. The possible value(s) of distance L in terms of wavelength lambda in figure which put A and B exactly out of phase with each other after all the reflected is/are

A ball is projected horizontally from an inclined plane with a velocity V, as shown in the figure. It will strike the plane after a time

A sound wave of frequency f propagating through air with a velocity c , is reflected from a surface which is moving away from the source with a constant speed v . Find the frequency of the reflected wave, measured by the observer at the position of the source.

A transverse sine wave of amplitude 10 cm and wavelength 200 cm travels from left to right along a long horizontal stretched, string with a speed of 100 cm/s. Take the origin at left end of the string. At time t = 0 the left end of the string is at the origin and is moving downward. Then the equation of the wave will be ( in CGS system )

CENGAGE PHYSICS ENGLISH-SUPERPOSITION AND STANDING WAVES-Single Correct
  1. Mark the correct statement.

    Text Solution

    |

  2. Which of the following statements is correct for stationary waves

    Text Solution

    |

  3. A sound wave of wavelength lambda travels towards the right horizonta...

    Text Solution

    |

  4. A sonometer wire of length l vibrates in fundamental mode when excited...

    Text Solution

    |

  5. Two closed - end pipes , when sounded together produce 5 beats//s. If...

    Text Solution

    |

  6. Velocity of sound in air is 320 m//s. The resonant pipe shown in Fig. ...

    Text Solution

    |

  7. Waves of frequency 1000 Hz are produced in a Kundt's tube . The total ...

    Text Solution

    |

  8. In a Kundt's tube , the length of the iron rod is 1 m. The stationary ...

    Text Solution

    |

  9. Two strings A and B made of same material are stretched by same tensio...

    Text Solution

    |

  10. A closed organ pipe and an open organ pipe have their first overtones...

    Text Solution

    |

  11. Two organ pipe , both closed at one end , have lengths l and l + Delta...

    Text Solution

    |

  12. A closed tube has a frequency n. If its length is doubled and radius i...

    Text Solution

    |

  13. In a resonance tube experiment , the first resonance is obtained for 1...

    Text Solution

    |

  14. Two waves having intensity I and 9I produce interference . If the resu...

    Text Solution

    |

  15. A sonometer wire , 100 cm in length has fundamental frequency of 330 H...

    Text Solution

    |

  16. In a resonance column experiment , the first resonance is obtained whe...

    Text Solution

    |

  17. A long glass tube is held vertically in water. A tuning fork is struck...

    Text Solution

    |

  18. A glass tube of 1.0 m length is filled with water . The water can be d...

    Text Solution

    |

  19. When the string of a sonometer of length L between the bridges vibrate...

    Text Solution

    |

  20. A standing tuning fork of frequency f is used to find the velocity of ...

    Text Solution

    |