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Waves of frequency 1000 Hz are produced ...

Waves of frequency `1000 Hz` are produced in a Kundt's tube . The total distance between `6` successive nodes is `82.5 cm`. The speed of sound in the gas filled in the tube is

A

`33 cm//s`

B

`33 m//s`

C

`330 m//s`

D

`660 m//s`

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The correct Answer is:
To find the speed of sound in the gas filled in the Kundt's tube, we can follow these steps: ### Step 1: Understand the relationship between nodes and wavelength In a standing wave, the distance between two successive nodes is equal to half the wavelength (λ/2). If we have 6 successive nodes, we can visualize them as follows: - Node 1 to Node 2: λ/2 - Node 2 to Node 3: λ/2 - Node 3 to Node 4: λ/2 - Node 4 to Node 5: λ/2 - Node 5 to Node 6: λ/2 Thus, the distance between 6 nodes consists of 5 segments of λ/2. ### Step 2: Calculate the total distance between nodes Given that the total distance between 6 successive nodes is 82.5 cm, we can express this as: \[ \text{Total distance} = 5 \times \frac{\lambda}{2} \] So, we can write: \[ 82.5 \text{ cm} = 5 \times \frac{\lambda}{2} \] ### Step 3: Solve for the wavelength (λ) Rearranging the equation to solve for λ: \[ \lambda = \frac{82.5 \text{ cm} \times 2}{5} \] Calculating this gives: \[ \lambda = \frac{165 \text{ cm}}{5} = 33 \text{ cm} \] ### Step 4: Convert the wavelength to meters Since we need the wavelength in meters for the speed calculation, we convert 33 cm to meters: \[ \lambda = 33 \text{ cm} = 0.33 \text{ m} \] ### Step 5: Use the speed formula The speed of sound (v) can be calculated using the formula: \[ v = f \times \lambda \] Where: - \( f \) is the frequency (1000 Hz) - \( \lambda \) is the wavelength (0.33 m) Substituting the values: \[ v = 1000 \text{ Hz} \times 0.33 \text{ m} = 330 \text{ m/s} \] ### Final Answer The speed of sound in the gas filled in the tube is **330 m/s**. ---

To find the speed of sound in the gas filled in the Kundt's tube, we can follow these steps: ### Step 1: Understand the relationship between nodes and wavelength In a standing wave, the distance between two successive nodes is equal to half the wavelength (λ/2). If we have 6 successive nodes, we can visualize them as follows: - Node 1 to Node 2: λ/2 - Node 2 to Node 3: λ/2 - Node 3 to Node 4: λ/2 ...
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