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An open pipe resonates with a tuning for...

An open pipe resonates with a tuning fork of frequency `500 Hz` . It is observed that two successive notes are formed at distance `16 and 46 cm` from the open end. The speed of sound in air in the pipe is

A

`230 m//s`

B

`300 m//s`

C

`320 m//s`

D

`360 m//s`

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To find the speed of sound in air in the pipe, we can follow these steps: ### Step 1: Understand the problem We have an open pipe that resonates with a tuning fork of frequency \( f = 500 \, \text{Hz} \). Two successive nodes are observed at distances \( d_1 = 16 \, \text{cm} \) and \( d_2 = 46 \, \text{cm} \) from the open end. ### Step 2: Identify the positions of nodes In an open pipe, the positions of the nodes can be expressed in terms of the wavelength \( \lambda \): - The first node (at \( d_1 \)) corresponds to \( \frac{\lambda}{4} \). - The second node (at \( d_2 \)) corresponds to \( \frac{3\lambda}{4} \). ### Step 3: Set up the equations From the distances given: 1. For the first node: \[ \frac{\lambda}{4} = 16 \, \text{cm} \] Therefore, we can express \( \lambda \): \[ \lambda = 4 \times 16 \, \text{cm} = 64 \, \text{cm} \] 2. For the second node: \[ \frac{3\lambda}{4} = 46 \, \text{cm} \] Thus, we can also express \( \lambda \): \[ \lambda = \frac{4 \times 46}{3} \, \text{cm} = \frac{184}{3} \, \text{cm} \approx 61.33 \, \text{cm} \] ### Step 4: Calculate the difference in distance The distance between the two nodes is: \[ d_2 - d_1 = 46 \, \text{cm} - 16 \, \text{cm} = 30 \, \text{cm} \] This distance corresponds to \( \frac{\lambda}{2} \) (since it represents one full wavelength from one node to the next). ### Step 5: Find the wavelength From the difference in distance: \[ \frac{\lambda}{2} = 30 \, \text{cm} \implies \lambda = 60 \, \text{cm} = 0.6 \, \text{m} \] ### Step 6: Calculate the speed of sound The speed of sound in the pipe can be calculated using the formula: \[ v = f \cdot \lambda \] Substituting the values we have: \[ v = 500 \, \text{Hz} \times 0.6 \, \text{m} = 300 \, \text{m/s} \] ### Conclusion The speed of sound in air in the pipe is \( 300 \, \text{m/s} \). ---

To find the speed of sound in air in the pipe, we can follow these steps: ### Step 1: Understand the problem We have an open pipe that resonates with a tuning fork of frequency \( f = 500 \, \text{Hz} \). Two successive nodes are observed at distances \( d_1 = 16 \, \text{cm} \) and \( d_2 = 46 \, \text{cm} \) from the open end. ### Step 2: Identify the positions of nodes In an open pipe, the positions of the nodes can be expressed in terms of the wavelength \( \lambda \): - The first node (at \( d_1 \)) corresponds to \( \frac{\lambda}{4} \). ...
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