Home
Class 11
PHYSICS
A stretched string of length 1 m fixed ...

A stretched string of length ` 1 m` fixed at both ends , having a mass of `5 xx 10^(-4) kg` is under a tension of `20 N`. It is plucked at a point situated at `25 cm` from one end . The stretched string would vibrate with a frequency of

A

`400 Hz`

B

`100 Hz`

C

`200 Hz`

D

`256 Hz`

Text Solution

AI Generated Solution

The correct Answer is:
To find the frequency of the vibrating string, we can follow these steps: ### Step 1: Determine the wavelength (λ) The string is fixed at both ends and is plucked at a point 25 cm from one end. This point acts as the first antinode, while the ends act as nodes. The distance from the fixed end to the first antinode is given as 25 cm (0.25 m). Since this distance represents a quarter of the wavelength (λ/4), we can express this relationship as: \[ \frac{\lambda}{4} = 0.25 \text{ m} \] To find the wavelength (λ), we multiply both sides by 4: \[ \lambda = 4 \times 0.25 = 1 \text{ m} \] ### Step 2: Calculate the linear mass density (μ) The linear mass density (μ) is defined as the mass per unit length of the string. Given that the mass of the string is \(5 \times 10^{-4} \text{ kg}\) and its length is 1 m, we can calculate μ as follows: \[ \mu = \frac{\text{mass}}{\text{length}} = \frac{5 \times 10^{-4} \text{ kg}}{1 \text{ m}} = 5 \times 10^{-4} \text{ kg/m} \] ### Step 3: Calculate the wave speed (v) The wave speed (v) on a string under tension (T) can be calculated using the formula: \[ v = \sqrt{\frac{T}{\mu}} \] Given that the tension \(T = 20 \text{ N}\) and \(\mu = 5 \times 10^{-4} \text{ kg/m}\), we can substitute these values into the formula: \[ v = \sqrt{\frac{20}{5 \times 10^{-4}}} \] Calculating the right-hand side: \[ v = \sqrt{40000} = 200 \text{ m/s} \] ### Step 4: Calculate the frequency (f) The frequency (f) of the wave can be calculated using the relationship between wave speed, frequency, and wavelength: \[ f = \frac{v}{\lambda} \] Substituting the values we have: \[ f = \frac{200 \text{ m/s}}{1 \text{ m}} = 200 \text{ Hz} \] ### Conclusion The frequency of the vibrating string is \(200 \text{ Hz}\).

To find the frequency of the vibrating string, we can follow these steps: ### Step 1: Determine the wavelength (λ) The string is fixed at both ends and is plucked at a point 25 cm from one end. This point acts as the first antinode, while the ends act as nodes. The distance from the fixed end to the first antinode is given as 25 cm (0.25 m). Since this distance represents a quarter of the wavelength (λ/4), we can express this relationship as: \[ \frac{\lambda}{4} = 0.25 \text{ m} ...
Promotional Banner

Topper's Solved these Questions

  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS ENGLISH|Exercise Multiple|26 Videos
  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS ENGLISH|Exercise Assertion - Reasoning|6 Videos
  • SUPERPOSITION AND STANDING WAVES

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|24 Videos
  • SOUND WAVES AND DOPPLER EFFECT

    CENGAGE PHYSICS ENGLISH|Exercise Integer|16 Videos
  • THERMODYNAMICS

    CENGAGE PHYSICS ENGLISH|Exercise 24|1 Videos

Similar Questions

Explore conceptually related problems

A one meter long string of mass 4.9 xx 10^(-4) kg is held under a tension of 19.6 N. IF the string vibrates in one segment, then the frequency of vibration will be

A stretched string of length L , fixed at both ends can sustain stationary waves of wavelength lamda Which of the following value of wavelength is not possible ?

A piano string having a mass per unit length equal to 5.00 xx 10^(3)kg//m is under a tension of 1350 N , Find the speed with which a wave travels on this string.

A string of density 7.5 gcm^(-3) and area of cross - section 0.2mm^(2) is stretched under a tension of 20 N. When it is plucked at the mid-point, the speed of the transverse wave on the wire is

A 1 m long rope, having a mass of 40 g , is fixed at one end and is tied to a light string at the other end. The tension in the string in 400 N . Find the wavelength in second overtone (in cm ).

A string of length 2 m is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of 500 Hz, then the waves would travel on its with a velocity of

A string of length 'L' is fixed at both ends . It is vibrating in its 3rd overtone with maximum amplitude 'a'. The amplitude at a distance L//3 from one end is

To decrease the fundamental frequency of a stretched string fixed at both ends one might

A string fixed at both ends, is vibrating in a particular mode of vibration. Vibration is such that a point on string is at maximum displacement and it is at a distance of one fourth of length of string from one end. The frequency of vibration in thus mode is 200 Hz . What will be the frequency of vibration when it vibrates in next mode such that the same point is at maximum displacement?

What is the second lowest frequency for standing waves on a wire that is 10.0 m long has a mass of 100 g and is stretched under a tension of 25 N which is fixed at both ends ?

CENGAGE PHYSICS ENGLISH-SUPERPOSITION AND STANDING WAVES-Single Correct
  1. Two instruments having stretched strings are being played in unison . ...

    Text Solution

    |

  2. The displacement xi in centimetres of a particle is xi = 3 sin 314 t +...

    Text Solution

    |

  3. A stretched string of length 1 m fixed at both ends , having a mass o...

    Text Solution

    |

  4. A sonometer wire supports a 4 kg load and vibrates in fundamental mode...

    Text Solution

    |

  5. A piano wire having a diameter of 0.90 mm is replaced by another wire ...

    Text Solution

    |

  6. In the sonometer experiment , a tuning fork of frequency 256 Hz is in ...

    Text Solution

    |

  7. An air column in a pipe, which is closed at one end, will be in resona...

    Text Solution

    |

  8. If v(1) , v(2) and v(3) are the fundamental frequencies of three segme...

    Text Solution

    |

  9. An organ pipe P(1) closed at one end vibrating in its first harmonic a...

    Text Solution

    |

  10. Two vibrating tuning forks produce progressive waves given by , y(1) =...

    Text Solution

    |

  11. A metal rod 40 cm long is dropped on to a wooden floor and rebounds in...

    Text Solution

    |

  12. A wave of frequency 100 Hz is sent along a string towards a fixed end....

    Text Solution

    |

  13. A sound wave starting from source S, follows two paths AOB and ACB to...

    Text Solution

    |

  14. Two standing bodies producing progressive waves are given by y(1) =...

    Text Solution

    |

  15. Ten tuning forks are arranged in increasing order of frequency is such...

    Text Solution

    |

  16. A long cylindrical tube carries a highly polished piston and has a sid...

    Text Solution

    |

  17. A sound wave of wavelength 0.40 m enters the tube at S. The smallest ...

    Text Solution

    |

  18. A sound wave starting from source S, follows two paths SEFD and SEABFD...

    Text Solution

    |

  19. An organ pipe A closed at one end vibrating in its fundamental freque...

    Text Solution

    |

  20. The displacement y of a particle executing periodic motion is given by...

    Text Solution

    |