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Two standing bodies producing progressiv...

Two standing bodies producing progressive waves are given by
` y_(1) = 4 sin 400 pi t and y_(2) = 3 sin 404 pi t`
One of these bodies situated very near to the ears of a person who will hear :

A

` 2 beats//s` with intensity ratio `4//3` between maxima and minima.

B

` 2 beats//s` with intensity ratio `49//1` between maxima and minima.

C

` 4 beats//s` with intensity ratio `7//2` between maxima and minima.

D

` 4 beats//s` with intensity ratio `4//3` between maxima and minima.

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The correct Answer is:
To solve the problem, we need to analyze the two progressive waves given by the equations: 1. \( y_1 = 4 \sin(400 \pi t) \) 2. \( y_2 = 3 \sin(404 \pi t) \) ### Step 1: Identify Angular Frequencies From the equations, we can identify the angular frequencies (\( \omega \)) of the two waves: - For wave 1: \( \omega_1 = 400 \pi \) - For wave 2: \( \omega_2 = 404 \pi \) ### Step 2: Calculate Frequencies Using the relationship \( \omega = 2 \pi f \), we can find the frequencies (\( f \)): - For wave 1: \[ f_1 = \frac{\omega_1}{2\pi} = \frac{400\pi}{2\pi} = 200 \text{ Hz} \] - For wave 2: \[ f_2 = \frac{\omega_2}{2\pi} = \frac{404\pi}{2\pi} = 202 \text{ Hz} \] ### Step 3: Calculate Beats Frequency The beat frequency (\( n \)) is given by the difference in frequencies: \[ n = f_2 - f_1 = 202 \text{ Hz} - 200 \text{ Hz} = 2 \text{ Hz} \] ### Step 4: Calculate Intensities Intensity (\( I \)) is proportional to the square of the amplitude (\( A \)). The ratio of intensities can be calculated as follows: \[ \frac{I_1}{I_2} = \frac{A_1^2}{A_2^2} \] Where: - \( A_1 = 4 \) - \( A_2 = 3 \) ### Step 5: Calculate Maximum and Minimum Intensities The maximum intensity occurs during constructive interference: \[ I_{max} \propto (A_1 + A_2)^2 = (4 + 3)^2 = 7^2 = 49 \] The minimum intensity occurs during destructive interference: \[ I_{min} \propto (A_1 - A_2)^2 = (4 - 3)^2 = 1^2 = 1 \] ### Step 6: Calculate the Ratio of Intensities The ratio of maximum to minimum intensity is: \[ \frac{I_{max}}{I_{min}} = \frac{49}{1} = 49 \] ### Final Answers - The beat frequency is \( 2 \text{ Hz} \). - The ratio of maximum to minimum intensity is \( 49:1 \).

To solve the problem, we need to analyze the two progressive waves given by the equations: 1. \( y_1 = 4 \sin(400 \pi t) \) 2. \( y_2 = 3 \sin(404 \pi t) \) ### Step 1: Identify Angular Frequencies From the equations, we can identify the angular frequencies (\( \omega \)) of the two waves: - For wave 1: \( \omega_1 = 400 \pi \) ...
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