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A 100 - m long rod of density 10.0 xx 10...

A `100 - m` long rod of density `10.0 xx 10^(4) kg//m^(3)` and having Young's modulus `Y = 10^(11) Pa`, is clamped at one end . It is hammered at the other free end. The longitudinal pulse goes to right end , gets reflected and again returns to the left end . How much time the pulse take to go back to initial point.

A

`0.1 s`

B

`0.2 s`

C

`0.3 s`

D

`2 s`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(s) = sqrt((Y)/(rho)) = sqrt((10^(11))/(10.0 xx 10^(4))) = 10^(3) m//s`
` t = ( 2l)/(V) = ( 2 xx 100)/(1000) = 0.2 s`
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