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For a certain organ pipe three successiv...

For a certain organ pipe three successive resonance frequencies are observed at 425Hz, 595 Hz and 765Hz respectively. If the speed of sound air is 340m/s, then the length of the pipe is

Text Solution

Verified by Experts

The correct Answer is:
`1`
Since frequencies are in odd number ratio , the pipe has to be a closed pipe.
Ratio of `3` frequencies `= 425 : 595 : 765`
`= 5 : 7 : 9`
So fundamental frequency ` = f = (425)/(5) = 85 Hz`
For fundamental frequency
`l = (v)/( 4f) = ( 340)/(4 xx85) = 1m`
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Knowledge Check

  • In a resonance tube, using a tuning fork of frequency 325 Hz, two successive resonance lengths are observed at 25.4 m and 77.4 cm respectively. The velocity of sound is air is

    A
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    B
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