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The function x = A sin^2 (omega)t + B co...

The function `x = A sin^2 (omega)t + B cos^2 (omega)t + Csin (omega)t cos (omega)t` represent (SHM) for which of the option(s).

A

For all value of `A,B and C` (except C = 0)

B

`A = -B, C = 2 B, amplitude = |B sqrt(2)|`

C

`A = B, C = 0`

D

`A = B, C = 2 B, amplitude = |B|`

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To determine for which conditions the function \( x = A \sin^2(\omega t) + B \cos^2(\omega t) + C \sin(\omega t) \cos(\omega t) \) represents Simple Harmonic Motion (SHM), we can simplify the expression using trigonometric identities. ### Step-by-Step Solution: 1. **Start with the given function:** \[ x = A \sin^2(\omega t) + B \cos^2(\omega t) + C \sin(\omega t) \cos(\omega t) \] 2. **Use trigonometric identities:** We can use the identities: - \( \sin^2(\theta) = \frac{1 - \cos(2\theta)}{2} \) - \( \cos^2(\theta) = \frac{1 + \cos(2\theta)}{2} \) - \( \sin(\theta) \cos(\theta) = \frac{1}{2} \sin(2\theta) \) Applying these identities: \[ \sin^2(\omega t) = \frac{1 - \cos(2\omega t)}{2}, \quad \cos^2(\omega t) = \frac{1 + \cos(2\omega t)}{2}, \quad \sin(\omega t) \cos(\omega t) = \frac{1}{2} \sin(2\omega t) \] 3. **Substituting the identities into the equation:** \[ x = A \left(\frac{1 - \cos(2\omega t)}{2}\right) + B \left(\frac{1 + \cos(2\omega t)}{2}\right) + C \left(\frac{1}{2} \sin(2\omega t)\right) \] Simplifying this gives: \[ x = \frac{A}{2} (1 - \cos(2\omega t)) + \frac{B}{2} (1 + \cos(2\omega t)) + \frac{C}{2} \sin(2\omega t) \] \[ x = \frac{A + B}{2} + \left(\frac{B - A}{2}\right) \cos(2\omega t) + \frac{C}{2} \sin(2\omega t) \] 4. **Rearranging the equation:** \[ x = \frac{A + B}{2} + \frac{B - A}{2} \cos(2\omega t) + \frac{C}{2} \sin(2\omega t) \] 5. **Identifying the form of SHM:** The equation can be expressed in the form: \[ x = D + E \cos(2\omega t) + F \sin(2\omega t) \] where \( D = \frac{A + B}{2} \), \( E = \frac{B - A}{2} \), and \( F = \frac{C}{2} \). 6. **Condition for SHM:** For \( x \) to represent SHM, the coefficients of \( \cos(2\omega t) \) and \( \sin(2\omega t) \) must not both be zero simultaneously. This means: \[ E^2 + F^2 > 0 \] or equivalently: \[ \left(\frac{B - A}{2}\right)^2 + \left(\frac{C}{2}\right)^2 > 0 \] ### Conclusion: The function represents SHM under the conditions that \( B - A \) and \( C \) are not both zero simultaneously, which leads us to the options provided in the question.

To determine for which conditions the function \( x = A \sin^2(\omega t) + B \cos^2(\omega t) + C \sin(\omega t) \cos(\omega t) \) represents Simple Harmonic Motion (SHM), we can simplify the expression using trigonometric identities. ### Step-by-Step Solution: 1. **Start with the given function:** \[ x = A \sin^2(\omega t) + B \cos^2(\omega t) + C \sin(\omega t) \cos(\omega t) \] ...
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