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A stationary source is emitting sound at a fixed frequency `f_(o)`, which is reflected by two cars approaching the source. The difference between the frequencies of sound reflected from the cars is 1.2 % of `f_(o)`. What is the difference in the speeds of the cars (in km per hour) to the nearest integer? Thee cars are moving at constant speeds much smaller than the speed of sound which is 330 `ms^(-1)`

Text Solution

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The correct Answer is:
7
`f_(app) = f_(0) (c+v)/(c-v)`, where `c` is speed of sound
`rArr df = (2f_(0)c)/((c-v)^(2)) dv ~~ (2 f_(0)c)/((c-v)^(2)) dv =(2f_(0))/(c) dv`…(i)
Given `df = (1.2)/(100) f_(0)`
From Eqs. (i) and (ii) `dv ~~ 2 m//s= 7 km//h`.
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