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An athlletic coach told his team that mu...

An athlletic coach told his team that muscle times speed equals power. What dimesions does he view for muscle?

A

`MLT^(-2)`

B

`ML^(2)T^(-2)`

C

`MLT^(-2)`

D

L

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The correct Answer is:
To solve the problem, we need to find the dimensions of "muscle" based on the relationship given by the athletic coach: muscle times speed equals power. Let's break this down step by step. ### Step 1: Understand the relationship The coach states that: \[ \text{Muscle} \times \text{Speed} = \text{Power} \] Let’s denote the dimension of muscle as \( [M] \). ### Step 2: Write the dimensions of speed Speed is defined as distance traveled per unit time. The dimension of speed can be expressed as: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{L}{T} \] Thus, the dimension of speed is: \[ [\text{Speed}] = [L][T^{-1}] \] ### Step 3: Write the dimensions of power Power is defined as the rate of doing work or energy transfer per unit time. The dimension of power can be expressed as: \[ \text{Power} = \frac{\text{Work}}{\text{Time}} \] The dimension of work (or energy) is: \[ \text{Work} = \text{Force} \times \text{Distance} = [M][L][T^{-2}][L] = [M][L^2][T^{-2}] \] Thus, the dimension of power is: \[ [\text{Power}] = \frac{[M][L^2][T^{-2}]}{[T]} = [M][L^2][T^{-3}] \] ### Step 4: Set up the equation with dimensions From the relationship given: \[ [M] \times [\text{Speed}] = [\text{Power}] \] Substituting the dimensions we have: \[ [M] \times [L][T^{-1}] = [M][L^2][T^{-3}] \] ### Step 5: Solve for the dimension of muscle Now we can express this as: \[ [M] \times [L][T^{-1}] = [M][L^2][T^{-3}] \] To isolate the dimension of muscle, we can rearrange the equation: \[ [M] = \frac{[M][L^2][T^{-3}]}{[L][T^{-1}]} \] ### Step 6: Simplify the right side \[ [M] = [M] \times \frac{[L^2]}{[L]} \times \frac{[T^{-3}]}{[T^{-1}]} \] This simplifies to: \[ [M] = [M] \times [L^{2-1}][T^{-3+1}] = [M] \times [L^1][T^{-2}] \] ### Step 7: Cancel out the common dimension Since we have \( [M] \) on both sides, we can cancel it out (assuming \( [M] \neq 0 \)): \[ 1 = [L^1][T^{-2}] \] Thus, the dimension of muscle can be expressed as: \[ [M] = [L^1][T^{-2}] \] ### Final Answer Thus, the dimension of muscle is: \[ [M][L^1][T^{-2}] \]

To solve the problem, we need to find the dimensions of "muscle" based on the relationship given by the athletic coach: muscle times speed equals power. Let's break this down step by step. ### Step 1: Understand the relationship The coach states that: \[ \text{Muscle} \times \text{Speed} = \text{Power} \] Let’s denote the dimension of muscle as \( [M] \). ...
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