If pressure P, velocity V and time T are taken as fundamental physical quantities, the dimensional formula of force if

Options

A. `PV^-2T^2`
B. `P^-1V^2T^-2`
C. `PVT^2`
D. `P^-1VT^2`

Answer

A

Explanation

Let `Fpropp^xV^yT^z`
by subsituting the following dimensions:
`[P]=[ML^-1T^-2][V]=[LT^-1]`,`[T]=[T]`
and comparing the dimension of both sides
`x=1`,`y=2`,`z=2`, so `F=PV^2T^2`