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Position of a body with acceleration a i...

Position of a body with acceleration `a` is given by `x=Ka^mt^n`, here t is time Find demension of m and n.

A

`m=1`,`n=1`

B

`m=1`,`n=2`

C

`m=2`,`n=1`

D

`m=2`,`n=2`

Text Solution

Verified by Experts

The correct Answer is:
B
As `x=Ka^mxxt^n`
`[M^0LT^0]=[LT^-2]^m[T]^n=[L^mT^(-2m+n)]`
`m=1` and `-2m+n=0implies=n=2`
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